This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
6∙162+2∙161+3∙160 = 6∙256+2∙16+3∙1 = 1536+32+3 = 157110
got It: 62316 =157110
Translate the number 157110 в octal like this:
the Integer part of the number is divided by the base of the new number system:
1571 | 8 | | | |
-1568 | 196 | 8 | | |
3 | -192 | 24 | 8 | |
| 4 | -24 | 3 | |
| | 0 | | |
|
the result of the conversion was:
157110 = 30438
answer: 62316 = 30438
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
62316 = 6 2 3 = 6(=0110) 2(=0010) 3(=0011) = 110001000112
answer: 62316 = 110001000112
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0110001000112 = 011 000 100 011 = 011(=3) 000(=0) 100(=4) 011(=3) = 30438
answer: 62316 = 30438