This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
0000100116 = 0 0 0 0 1 0 0 1 = 0(=0000) 0(=0000) 0(=0000) 0(=0000) 1(=0001) 0(=0000) 0(=0000) 1(=0001) = 10000000000012
answer: 0000100116 = 10000000000012
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙167+0∙166+0∙165+0∙164+1∙163+0∙162+0∙161+1∙160 = 0∙268435456+0∙16777216+0∙1048576+0∙65536+1∙4096+0∙256+0∙16+1∙1 = 0+0+0+0+4096+0+0+1 = 409710
got It: 0000100116 =409710
Translate the number 409710 в binary like this:
the Integer part of the number is divided by the base of the new number system:
4097 | 2 | | | | | | | | | | | | |
-4096 | 2048 | 2 | | | | | | | | | | | |
1 | -2048 | 1024 | 2 | | | | | | | | | | |
| 0 | -1024 | 512 | 2 | | | | | | | | | |
| | 0 | -512 | 256 | 2 | | | | | | | | |
| | | 0 | -256 | 128 | 2 | | | | | | | |
| | | | 0 | -128 | 64 | 2 | | | | | | |
| | | | | 0 | -64 | 32 | 2 | | | | | |
| | | | | | 0 | -32 | 16 | 2 | | | | |
| | | | | | | 0 | -16 | 8 | 2 | | | |
| | | | | | | | 0 | -8 | 4 | 2 | | |
| | | | | | | | | 0 | -4 | 2 | 2 | |
| | | | | | | | | | 0 | -2 | 1 | |
| | | | | | | | | | | 0 | | |
|
the result of the conversion was:
409710 = 10000000000012
answer: 0000100116 = 10000000000012