This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
1F8E616 = 1 F 8 E 6 = 1(=0001) F(=1111) 8(=1000) E(=1110) 6(=0110) = 111111000111001102
answer: 1F8E616 = 111111000111001102
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙164+15∙163+8∙162+14∙161+6∙160 = 1∙65536+15∙4096+8∙256+14∙16+6∙1 = 65536+61440+2048+224+6 = 12925410
got It: 1F8E616 =12925410
Translate the number 12925410 в binary like this:
the Integer part of the number is divided by the base of the new number system:
129254 | 2 | | | | | | | | | | | | | | | | |
-129254 | 64627 | 2 | | | | | | | | | | | | | | | |
0 | -64626 | 32313 | 2 | | | | | | | | | | | | | | |
| 1 | -32312 | 16156 | 2 | | | | | | | | | | | | | |
| | 1 | -16156 | 8078 | 2 | | | | | | | | | | | | |
| | | 0 | -8078 | 4039 | 2 | | | | | | | | | | | |
| | | | 0 | -4038 | 2019 | 2 | | | | | | | | | | |
| | | | | 1 | -2018 | 1009 | 2 | | | | | | | | | |
| | | | | | 1 | -1008 | 504 | 2 | | | | | | | | |
| | | | | | | 1 | -504 | 252 | 2 | | | | | | | |
| | | | | | | | 0 | -252 | 126 | 2 | | | | | | |
| | | | | | | | | 0 | -126 | 63 | 2 | | | | | |
| | | | | | | | | | 0 | -62 | 31 | 2 | | | | |
| | | | | | | | | | | 1 | -30 | 15 | 2 | | | |
| | | | | | | | | | | | 1 | -14 | 7 | 2 | | |
| | | | | | | | | | | | | 1 | -6 | 3 | 2 | |
| | | | | | | | | | | | | | 1 | -2 | 1 | |
| | | | | | | | | | | | | | | 1 | | |
|
the result of the conversion was:
12925410 = 111111000111001102
answer: 1F8E616 = 111111000111001102