This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0100110001110012 = 010 011 000 111 001 = 010(=2) 011(=3) 000(=0) 111(=7) 001(=1) = 230718
answer: 100110001110012 = 230718
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙214+1∙213+0∙212+0∙211+1∙210+1∙29+0∙28+0∙27+0∙26+1∙25+1∙24+1∙23+0∙22+0∙21+1∙20 = 0∙16384+1∙8192+0∙4096+0∙2048+1∙1024+1∙512+0∙256+0∙128+0∙64+1∙32+1∙16+1∙8+0∙4+0∙2+1∙1 = 0+8192+0+0+1024+512+0+0+0+32+16+8+0+0+1 = 978510
got It: 0100110001110012 =978510
Translate the number 978510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
9785 | 8 | | | | |
-9784 | 1223 | 8 | | | |
1 | -1216 | 152 | 8 | | |
| 7 | -152 | 19 | 8 | |
| | 0 | -16 | 2 | |
| | | 3 | | |
|
the result of the conversion was:
978510 = 230718
answer: 100110001110012 = 230718