This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
010.1.1.102 = 010. 1.1 .10 = 010(=2). 1.1(=3) .10(=2) = 2.328
answer: 10.1.1.12 = 2.328
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙22+1∙21+0∙20+1∙2-1+.∙2-2+1∙2-3+.∙2-4+1∙2-5+0∙2-6 = 0∙4+1∙2+0∙1+1∙0.5+.∙0.25+1∙0.125+.∙0.0625+1∙0.03125+0∙0.015625 = 0+2+0+0.5+0+0.125+0+0.03125+0 = 2.6562510
got It: 010.1.1.102 =2.6562510
Translate the number 2.6562510 в octal like this:
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 65625*8 |
5 | .25*8 |
2 | .0*8 |
the result of the conversion was:
2.6562510 = 2.528
answer: 10.1.1.12 = 2.528