This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
6∙84+0∙83+0∙82+0∙81+0∙80 = 6∙4096+0∙512+0∙64+0∙8+0∙1 = 24576+0+0+0+0 = 2457610
got It: 600008 =2457610
Translate the number 2457610 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
24576 | 16 | | | |
-24576 | 1536 | 16 | | |
0 | -1536 | 96 | 16 | |
| 0 | -96 | 6 | |
| | 0 | | |
|
the result of the conversion was:
2457610 = 600016
answer: 600008 = 600016
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
600008 = 6 0 0 0 0 = 6(=110) 0(=000) 0(=000) 0(=000) 0(=000) = 1100000000000002
answer: 600008 = 1100000000000002
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
01100000000000002 = 0110 0000 0000 0000 = 0110(=6) 0000(=0) 0000(=0) 0000(=0) = 600016
answer: 01100000000000008 = 600016