This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
300016 = 3 0 0 0 = 3(=0011) 0(=0000) 0(=0000) 0(=0000) = 110000000000002
answer: 300016 = 110000000000002
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
3∙163+0∙162+0∙161+0∙160 = 3∙4096+0∙256+0∙16+0∙1 = 12288+0+0+0 = 1228810
got It: 300016 =1228810
Translate the number 1228810 в binary like this:
the Integer part of the number is divided by the base of the new number system:
12288 | 2 | | | | | | | | | | | | | |
-12288 | 6144 | 2 | | | | | | | | | | | | |
0 | -6144 | 3072 | 2 | | | | | | | | | | | |
| 0 | -3072 | 1536 | 2 | | | | | | | | | | |
| | 0 | -1536 | 768 | 2 | | | | | | | | | |
| | | 0 | -768 | 384 | 2 | | | | | | | | |
| | | | 0 | -384 | 192 | 2 | | | | | | | |
| | | | | 0 | -192 | 96 | 2 | | | | | | |
| | | | | | 0 | -96 | 48 | 2 | | | | | |
| | | | | | | 0 | -48 | 24 | 2 | | | | |
| | | | | | | | 0 | -24 | 12 | 2 | | | |
| | | | | | | | | 0 | -12 | 6 | 2 | | |
| | | | | | | | | | 0 | -6 | 3 | 2 | |
| | | | | | | | | | | 0 | -2 | 1 | |
| | | | | | | | | | | | 1 | | |
|
the result of the conversion was:
1228810 = 110000000000002
answer: 300016 = 110000000000002