This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s make a direct translation from binary to post-binary like this:
1100110102 = 110 011 010 = 110(=6) 011(=3) 010(=2) = 6328
answer: 1100110102 = 6328
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙28+1∙27+0∙26+0∙25+1∙24+1∙23+0∙22+1∙21+0∙20 = 1∙256+1∙128+0∙64+0∙32+1∙16+1∙8+0∙4+1∙2+0∙1 = 256+128+0+0+16+8+0+2+0 = 41010
got It: 1100110102 =41010
Translate the number 41010 в octal like this:
the Integer part of the number is divided by the base of the new number system:
410 | 8 | | |
-408 | 51 | 8 | |
2 | -48 | 6 | |
| 3 | | |
|
the result of the conversion was:
41010 = 6328
answer: 1100110102 = 6328