This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
010101101.0110102 = 010 101 101. 011 010 = 010(=2) 101(=5) 101(=5). 011(=3) 010(=2) = 255.328
answer: 10101101.011012 = 255.328
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙28+1∙27+0∙26+1∙25+0∙24+1∙23+1∙22+0∙21+1∙20+0∙2-1+1∙2-2+1∙2-3+0∙2-4+1∙2-5+0∙2-6 = 0∙256+1∙128+0∙64+1∙32+0∙16+1∙8+1∙4+0∙2+1∙1+0∙0.5+1∙0.25+1∙0.125+0∙0.0625+1∙0.03125+0∙0.015625 = 0+128+0+32+0+8+4+0+1+0+0.25+0.125+0+0.03125+0 = 173.4062510
got It: 010101101.0110102 =173.4062510
Translate the number 173.4062510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
173 | 8 | | |
-168 | 21 | 8 | |
5 | -16 | 2 | |
| 5 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 40625*8 |
3 | .25*8 |
2 | .0*8 |
the result of the conversion was:
173.4062510 = 255.328
answer: 10101101.011012 = 255.328