This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
5∙81+5∙80+2∙8-1+7∙8-2 = 5∙8+5∙1+2∙0.125+7∙0.015625 = 40+5+0.25+0.109375 = 45.35937510
got It: 55.278 =45.35937510
Translate the number 45.35937510 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
45 | 16 | |
-32 | 2 | |
D | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 359375*16 |
5 | .75*16 |
C | .0*16 |
the result of the conversion was:
45.35937510 = 2D.5C16
answer: 55.278 = 2D.5C16
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
55.278 = 5 5. 2 7 = 5(=101) 5(=101). 2(=010) 7(=111) = 101101.0101112
answer: 55.278 = 101101.0101112
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s do a direct translation from binary to hexadecimal like this:
00101101.010111002 = 0010 1101. 0101 1100 = 0010(=2) 1101(=D). 0101(=5) 1100(=C) = 2D.5C16
answer: 00101101.010111008 = 2D.5C16