This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
111011001.1102 = 111 011 001. 110 = 111(=7) 011(=3) 001(=1). 110(=6) = 731.68
answer: 111011001.112 = 731.68
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙28+1∙27+1∙26+0∙25+1∙24+1∙23+0∙22+0∙21+1∙20+1∙2-1+1∙2-2+0∙2-3 = 1∙256+1∙128+1∙64+0∙32+1∙16+1∙8+0∙4+0∙2+1∙1+1∙0.5+1∙0.25+0∙0.125 = 256+128+64+0+16+8+0+0+1+0.5+0.25+0 = 473.7510
got It: 111011001.1102 =473.7510
Translate the number 473.7510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
473 | 8 | | |
-472 | 59 | 8 | |
1 | -56 | 7 | |
| 3 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 75*8 |
6 | .0*8 |
the result of the conversion was:
473.7510 = 731.68
answer: 111011001.112 = 731.68