This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
4∙83+6∙82+7∙81+3∙80 = 4∙512+6∙64+7∙8+3∙1 = 2048+384+56+3 = 249110
got It: 46738 =249110
Translate the number 249110 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
2491 | 16 | | |
-2480 | 155 | 16 | |
B | -144 | 9 | |
| B | | |
|
the result of the conversion was:
249110 = 9BB16
answer: 46738 = 9BB16
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
46738 = 4 6 7 3 = 4(=100) 6(=110) 7(=111) 3(=011) = 1001101110112
answer: 46738 = 1001101110112
let\'s do a direct translation from binary to hexadecimal like this:
1001101110112 = 1001 1011 1011 = 1001(=9) 1011(=B) 1011(=B) = 9BB16
answer: 1001101110118 = 9BB16