This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
2438616 = 2 4 3 8 6 = 2(=0010) 4(=0100) 3(=0011) 8(=1000) 6(=0110) = 1001000011100001102
answer: 2438616 = 1001000011100001102
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
2∙164+4∙163+3∙162+8∙161+6∙160 = 2∙65536+4∙4096+3∙256+8∙16+6∙1 = 131072+16384+768+128+6 = 14835810
got It: 2438616 =14835810
Translate the number 14835810 в binary like this:
the Integer part of the number is divided by the base of the new number system:
148358 | 2 | | | | | | | | | | | | | | | | | |
-148358 | 74179 | 2 | | | | | | | | | | | | | | | | |
0 | -74178 | 37089 | 2 | | | | | | | | | | | | | | | |
| 1 | -37088 | 18544 | 2 | | | | | | | | | | | | | | |
| | 1 | -18544 | 9272 | 2 | | | | | | | | | | | | | |
| | | 0 | -9272 | 4636 | 2 | | | | | | | | | | | | |
| | | | 0 | -4636 | 2318 | 2 | | | | | | | | | | | |
| | | | | 0 | -2318 | 1159 | 2 | | | | | | | | | | |
| | | | | | 0 | -1158 | 579 | 2 | | | | | | | | | |
| | | | | | | 1 | -578 | 289 | 2 | | | | | | | | |
| | | | | | | | 1 | -288 | 144 | 2 | | | | | | | |
| | | | | | | | | 1 | -144 | 72 | 2 | | | | | | |
| | | | | | | | | | 0 | -72 | 36 | 2 | | | | | |
| | | | | | | | | | | 0 | -36 | 18 | 2 | | | | |
| | | | | | | | | | | | 0 | -18 | 9 | 2 | | | |
| | | | | | | | | | | | | 0 | -8 | 4 | 2 | | |
| | | | | | | | | | | | | | 1 | -4 | 2 | 2 | |
| | | | | | | | | | | | | | | 0 | -2 | 1 | |
| | | | | | | | | | | | | | | | 0 | | |
|
the result of the conversion was:
14835810 = 1001000011100001102
answer: 2438616 = 1001000011100001102