This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
2∙82+3∙81+6∙80+1∙8-1+7∙8-2 = 2∙64+3∙8+6∙1+1∙0.125+7∙0.015625 = 128+24+6+0.125+0.109375 = 158.23437510
got It: 236.178 =158.23437510
Translate the number 158.23437510 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
158 | 16 | |
-144 | 9 | |
E | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 234375*16 |
3 | .75*16 |
C | .0*16 |
the result of the conversion was:
158.23437510 = 9E.3C16
answer: 236.178 = 9E.3C16
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
236.178 = 2 3 6. 1 7 = 2(=010) 3(=011) 6(=110). 1(=001) 7(=111) = 010011110.0011112
answer: 236.178 = 10011110.0011112
Fill in the number with missing zeros on the right
let\'s do a direct translation from binary to hexadecimal like this:
10011110.001111002 = 1001 1110. 0011 1100 = 1001(=9) 1110(=E). 0011(=3) 1100(=C) = 9E.3C16
answer: 10011110.001111008 = 9E.3C16