This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
111011.0010102 = 111 011. 001 010 = 111(=7) 011(=3). 001(=1) 010(=2) = 73.128
answer: 111011.001012 = 73.128
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙25+1∙24+1∙23+0∙22+1∙21+1∙20+0∙2-1+0∙2-2+1∙2-3+0∙2-4+1∙2-5+0∙2-6 = 1∙32+1∙16+1∙8+0∙4+1∙2+1∙1+0∙0.5+0∙0.25+1∙0.125+0∙0.0625+1∙0.03125+0∙0.015625 = 32+16+8+0+2+1+0+0+0.125+0+0.03125+0 = 59.1562510
got It: 111011.0010102 =59.1562510
Translate the number 59.1562510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
59 | 8 | |
-56 | 7 | |
3 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 15625*8 |
1 | .25*8 |
2 | .0*8 |
the result of the conversion was:
59.1562510 = 73.128
answer: 111011.001012 = 73.128