This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from octal to binary like this:
1672.47534121728 = 1 6 7 2. 4 7 5 3 4 1 2 1 7 2 = 1(=001) 6(=110) 7(=111) 2(=010). 4(=100) 7(=111) 5(=101) 3(=011) 4(=100) 1(=001) 2(=010) 1(=001) 7(=111) 2(=010) = 001110111010.1001111010111000010100011110102
the Final answer: 1672.47534121728 = 1110111010.100111101011100001010001111012
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙83+6∙82+7∙81+2∙80+4∙8-1+7∙8-2+5∙8-3+3∙8-4+4∙8-5+1∙8-6+2∙8-7+1∙8-8+7∙8-9+2∙8-10 = 1∙512+6∙64+7∙8+2∙1+4∙0.125+7∙0.015625+5∙0.001953125+3∙0.000244140625+4∙3.0517578125E-5+1∙3.814697265625E-6+2∙4.7683715820312E-7+1∙5.9604644775391E-8+7∙7.4505805969238E-9+2∙9.3132257461548E-10 = 512+384+56+2+0.5+0.109375+0.009765625+0.000732421875+0.0001220703125+3.814697265625E-6+9.5367431640625E-7+5.9604644775391E-8+5.2154064178467E-8+1.862645149231E-9 = 954.6199999991804410
got It: 1672.47534121728 =954.6199999991804410
Translate the number 954.6199999991804410 в binary like this:
the Integer part of the number is divided by the base of the new number system:
954 | 2 | | | | | | | | | |
-954 | 477 | 2 | | | | | | | | |
0 | -476 | 238 | 2 | | | | | | | |
| 1 | -238 | 119 | 2 | | | | | | |
| | 0 | -118 | 59 | 2 | | | | | |
| | | 1 | -58 | 29 | 2 | | | | |
| | | | 1 | -28 | 14 | 2 | | | |
| | | | | 1 | -14 | 7 | 2 | | |
| | | | | | 0 | -6 | 3 | 2 | |
| | | | | | | 1 | -2 | 1 | |
| | | | | | | | 1 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 61999999918044*2 |
1 | .24*2 |
0 | .48*2 |
0 | .96*2 |
1 | .92*2 |
1 | .84*2 |
1 | .68*2 |
1 | .36*2 |
0 | .72*2 |
1 | .44*2 |
0 | .88*2 |
the result of the conversion was:
954.6199999991804410 = 1110111010.10011110102
the Final answer: 1672.47534121728 = 1110111010.10011110102