This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
0∙163+0∙162+6∙161+14∙160 = 0∙4096+0∙256+6∙16+14∙1 = 0+0+96+14 = 11010
got It: 006e16 =11010
Translate the number 11010 в octal like this:
the Integer part of the number is divided by the base of the new number system:
110 | 8 | | |
-104 | 13 | 8 | |
6 | -8 | 1 | |
| 5 | | |
|
the result of the conversion was:
11010 = 1568
answer: 006e16 = 1568
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
006e16 = 0 0 6 e = 0(=0000) 0(=0000) 6(=0110) e(=1110) = 11011102
answer: 006e16 = 11011102
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0011011102 = 001 101 110 = 001(=1) 101(=5) 110(=6) = 1568
answer: 006e16 = 1568