This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0110100012 = 011 010 001 = 011(=3) 010(=2) 001(=1) = 3218
answer: 110100012 = 3218
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙28+1∙27+1∙26+0∙25+1∙24+0∙23+0∙22+0∙21+1∙20 = 0∙256+1∙128+1∙64+0∙32+1∙16+0∙8+0∙4+0∙2+1∙1 = 0+128+64+0+16+0+0+0+1 = 20910
got It: 0110100012 =20910
Translate the number 20910 в octal like this:
the Integer part of the number is divided by the base of the new number system:
209 | 8 | | |
-208 | 26 | 8 | |
1 | -24 | 3 | |
| 2 | | |
|
the result of the conversion was:
20910 = 3218
answer: 110100012 = 3218