This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
1AF716 = 1 A F 7 = 1(=0001) A(=1010) F(=1111) 7(=0111) = 11010111101112
answer: 1AF716 = 11010111101112
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙163+10∙162+15∙161+7∙160 = 1∙4096+10∙256+15∙16+7∙1 = 4096+2560+240+7 = 690310
got It: 1AF716 =690310
Translate the number 690310 в binary like this:
the Integer part of the number is divided by the base of the new number system:
6903 | 2 | | | | | | | | | | | | |
-6902 | 3451 | 2 | | | | | | | | | | | |
1 | -3450 | 1725 | 2 | | | | | | | | | | |
| 1 | -1724 | 862 | 2 | | | | | | | | | |
| | 1 | -862 | 431 | 2 | | | | | | | | |
| | | 0 | -430 | 215 | 2 | | | | | | | |
| | | | 1 | -214 | 107 | 2 | | | | | | |
| | | | | 1 | -106 | 53 | 2 | | | | | |
| | | | | | 1 | -52 | 26 | 2 | | | | |
| | | | | | | 1 | -26 | 13 | 2 | | | |
| | | | | | | | 0 | -12 | 6 | 2 | | |
| | | | | | | | | 1 | -6 | 3 | 2 | |
| | | | | | | | | | 0 | -2 | 1 | |
| | | | | | | | | | | 1 | | |
|
the result of the conversion was:
690310 = 11010111101112
answer: 1AF716 = 11010111101112