This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
10∙162+11∙161+12∙160+13∙16-1+14∙16-2 = 10∙256+11∙16+12∙1+13∙0.0625+14∙0.00390625 = 2560+176+12+0.8125+0.0546875 = 2748.867187510
got It: abc.de16 =2748.867187510
Translate the number 2748.867187510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
2748 | 8 | | | |
-2744 | 343 | 8 | | |
4 | -336 | 42 | 8 | |
| 7 | -40 | 5 | |
| | 2 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 8671875*8 |
6 | .9375*8 |
7 | .5*8 |
4 | .0*8 |
the result of the conversion was:
2748.867187510 = 5274.6748
answer: abc.de16 = 5274.6748
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
abc.de16 = a b c. d e = a(=1010) b(=1011) c(=1100). d(=1101) e(=1110) = 101010111100.11011112
answer: abc.de16 = 101010111100.11011112
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
101010111100.1101111002 = 101 010 111 100. 110 111 100 = 101(=5) 010(=2) 111(=7) 100(=4). 110(=6) 111(=7) 100(=4) = 5274.6748
answer: abc.de16 = 5274.6748