This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from octal to binary like this:
65218 = 6 5 2 1 = 6(=110) 5(=101) 2(=010) 1(=001) = 1101010100012
answer: 65218 = 1101010100012
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
6∙83+5∙82+2∙81+1∙80 = 6∙512+5∙64+2∙8+1∙1 = 3072+320+16+1 = 340910
got It: 65218 =340910
Translate the number 340910 в binary like this:
the Integer part of the number is divided by the base of the new number system:
3409 | 2 | | | | | | | | | | | |
-3408 | 1704 | 2 | | | | | | | | | | |
1 | -1704 | 852 | 2 | | | | | | | | | |
| 0 | -852 | 426 | 2 | | | | | | | | |
| | 0 | -426 | 213 | 2 | | | | | | | |
| | | 0 | -212 | 106 | 2 | | | | | | |
| | | | 1 | -106 | 53 | 2 | | | | | |
| | | | | 0 | -52 | 26 | 2 | | | | |
| | | | | | 1 | -26 | 13 | 2 | | | |
| | | | | | | 0 | -12 | 6 | 2 | | |
| | | | | | | | 1 | -6 | 3 | 2 | |
| | | | | | | | | 0 | -2 | 1 | |
| | | | | | | | | | 1 | | |
|
the result of the conversion was:
340910 = 1101010100012
answer: 65218 = 1101010100012