This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from octal to binary like this:
1101.1108 = 1 1 0 1. 1 1 0 = 1(=001) 1(=001) 0(=000) 1(=001). 1(=001) 1(=001) 0(=000) = 001001000001.0010010002
answer: 1101.1108 = 1001000001.0010012
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙83+1∙82+0∙81+1∙80+1∙8-1+1∙8-2+0∙8-3 = 1∙512+1∙64+0∙8+1∙1+1∙0.125+1∙0.015625+0∙0.001953125 = 512+64+0+1+0.125+0.015625+0 = 577.14062510
got It: 1101.1108 =577.14062510
Translate the number 577.14062510 в binary like this:
the Integer part of the number is divided by the base of the new number system:
577 | 2 | | | | | | | | | |
-576 | 288 | 2 | | | | | | | | |
1 | -288 | 144 | 2 | | | | | | | |
| 0 | -144 | 72 | 2 | | | | | | |
| | 0 | -72 | 36 | 2 | | | | | |
| | | 0 | -36 | 18 | 2 | | | | |
| | | | 0 | -18 | 9 | 2 | | | |
| | | | | 0 | -8 | 4 | 2 | | |
| | | | | | 1 | -4 | 2 | 2 | |
| | | | | | | 0 | -2 | 1 | |
| | | | | | | | 0 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 140625*2 |
0 | .28125*2 |
0 | .5625*2 |
1 | .125*2 |
0 | .25*2 |
0 | .5*2 |
1 | .0*2 |
the result of the conversion was:
577.14062510 = 1001000001.0010012
answer: 1101.1108 = 1001000001.0010012