This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
000.1001110110102 = 000. 100 111 011 010 = 000(=0). 100(=4) 111(=7) 011(=3) 010(=2) = 0.47328
answer: 0.100111011012 = 0.47328
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙22+0∙21+0∙20+1∙2-1+0∙2-2+0∙2-3+1∙2-4+1∙2-5+1∙2-6+0∙2-7+1∙2-8+1∙2-9+0∙2-10+1∙2-11+0∙2-12 = 0∙4+0∙2+0∙1+1∙0.5+0∙0.25+0∙0.125+1∙0.0625+1∙0.03125+1∙0.015625+0∙0.0078125+1∙0.00390625+1∙0.001953125+0∙0.0009765625+1∙0.00048828125+0∙0.000244140625 = 0+0+0+0.5+0+0+0.0625+0.03125+0.015625+0+0.00390625+0.001953125+0+0.00048828125+0 = 0.6157226562510
got It: 000.1001110110102 =0.6157226562510
Translate the number 0.6157226562510 в octal like this:
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 61572265625*8 |
4 | .92578*8 |
7 | .40625*8 |
3 | .25*8 |
2 | .0*8 |
the result of the conversion was:
0.6157226562510 = 0.47328
answer: 0.100111011012 = 0.47328