This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
ED16 = E D = E(=1110) D(=1101) = 111011012
answer: ED16 = 111011012
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
14∙161+13∙160 = 14∙16+13∙1 = 224+13 = 23710
got It: ED16 =23710
Translate the number 23710 в binary like this:
the Integer part of the number is divided by the base of the new number system:
237 | 2 | | | | | | | |
-236 | 118 | 2 | | | | | | |
1 | -118 | 59 | 2 | | | | | |
| 0 | -58 | 29 | 2 | | | | |
| | 1 | -28 | 14 | 2 | | | |
| | | 1 | -14 | 7 | 2 | | |
| | | | 0 | -6 | 3 | 2 | |
| | | | | 1 | -2 | 1 | |
| | | | | | 1 | | |
|
the result of the conversion was:
23710 = 111011012
answer: ED16 = 111011012