This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
011001001101.1011011002 = 011 001 001 101. 101 101 100 = 011(=3) 001(=1) 001(=1) 101(=5). 101(=5) 101(=5) 100(=4) = 3115.5548
the Final answer: 11001001101.10110112 = 3115.5548
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙211+1∙210+1∙29+0∙28+0∙27+1∙26+0∙25+0∙24+1∙23+1∙22+0∙21+1∙20+1∙2-1+0∙2-2+1∙2-3+1∙2-4+0∙2-5+1∙2-6+1∙2-7+0∙2-8+0∙2-9 = 0∙2048+1∙1024+1∙512+0∙256+0∙128+1∙64+0∙32+0∙16+1∙8+1∙4+0∙2+1∙1+1∙0.5+0∙0.25+1∙0.125+1∙0.0625+0∙0.03125+1∙0.015625+1∙0.0078125+0∙0.00390625+0∙0.001953125 = 0+1024+512+0+0+64+0+0+8+4+0+1+0.5+0+0.125+0.0625+0+0.015625+0.0078125+0+0 = 1613.710937510
got It: 011001001101.1011011002 =1613.710937510
Translate the number 1613.710937510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
1613 | 8 | | | |
-1608 | 201 | 8 | | |
5 | -200 | 25 | 8 | |
| 1 | -24 | 3 | |
| | 1 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 7109375*8 |
5 | .6875*8 |
5 | .5*8 |
4 | .0*8 |
the result of the conversion was:
1613.710937510 = 3115.5548
the Final answer: 11001001101.10110112 = 3115.5548