This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
7∙162+15∙161+5∙160 = 7∙256+15∙16+5∙1 = 1792+240+5 = 203710
got It: 7F516 =203710
Translate the number 203710 в octal like this:
the Integer part of the number is divided by the base of the new number system:
2037 | 8 | | | |
-2032 | 254 | 8 | | |
5 | -248 | 31 | 8 | |
| 6 | -24 | 3 | |
| | 7 | | |
|
the result of the conversion was:
203710 = 37658
answer: 7F516 = 37658
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
7F516 = 7 F 5 = 7(=0111) F(=1111) 5(=0101) = 111111101012
answer: 7F516 = 111111101012
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0111111101012 = 011 111 110 101 = 011(=3) 111(=7) 110(=6) 101(=5) = 37658
answer: 7F516 = 37658