This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s make a direct translation from binary to post-binary like this:
0111002 = 011 100 = 011(=3) 100(=4) = 348
answer: 0111002 = 348
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙25+1∙24+1∙23+1∙22+0∙21+0∙20 = 0∙32+1∙16+1∙8+1∙4+0∙2+0∙1 = 0+16+8+4+0+0 = 2810
got It: 0111002 =2810
Translate the number 2810 в octal like this:
the Integer part of the number is divided by the base of the new number system:
28 | 8 | |
-24 | 3 | |
4 | | |
|
the result of the conversion was:
2810 = 348
answer: 0111002 = 348