This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
011110011.1000102 = 011 110 011. 100 010 = 011(=3) 110(=6) 011(=3). 100(=4) 010(=2) = 363.428
answer: 11110011.100012 = 363.428
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙28+1∙27+1∙26+1∙25+1∙24+0∙23+0∙22+1∙21+1∙20+1∙2-1+0∙2-2+0∙2-3+0∙2-4+1∙2-5+0∙2-6 = 0∙256+1∙128+1∙64+1∙32+1∙16+0∙8+0∙4+1∙2+1∙1+1∙0.5+0∙0.25+0∙0.125+0∙0.0625+1∙0.03125+0∙0.015625 = 0+128+64+32+16+0+0+2+1+0.5+0+0+0+0.03125+0 = 243.5312510
got It: 011110011.1000102 =243.5312510
Translate the number 243.5312510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
243 | 8 | | |
-240 | 30 | 8 | |
3 | -24 | 3 | |
| 6 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 53125*8 |
4 | .25*8 |
2 | .0*8 |
the result of the conversion was:
243.5312510 = 363.428
answer: 11110011.100012 = 363.428