This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
10∙161+12∙160 = 10∙16+12∙1 = 160+12 = 17210
got It: Ac16 =17210
Translate the number 17210 в octal like this:
the Integer part of the number is divided by the base of the new number system:
172 | 8 | | |
-168 | 21 | 8 | |
4 | -16 | 2 | |
| 5 | | |
|
the result of the conversion was:
17210 = 2548
answer: Ac16 = 2548
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
Ac16 = A c = A(=1010) c(=1100) = 101011002
answer: Ac16 = 101011002
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0101011002 = 010 101 100 = 010(=2) 101(=5) 100(=4) = 2548
answer: Ac16 = 2548