This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
AC416 = A C 4 = A(=1010) C(=1100) 4(=0100) = 1010110001002
answer: AC416 = 1010110001002
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
10∙162+12∙161+4∙160 = 10∙256+12∙16+4∙1 = 2560+192+4 = 275610
got It: AC416 =275610
Translate the number 275610 в binary like this:
the Integer part of the number is divided by the base of the new number system:
2756 | 2 | | | | | | | | | | | |
-2756 | 1378 | 2 | | | | | | | | | | |
0 | -1378 | 689 | 2 | | | | | | | | | |
| 0 | -688 | 344 | 2 | | | | | | | | |
| | 1 | -344 | 172 | 2 | | | | | | | |
| | | 0 | -172 | 86 | 2 | | | | | | |
| | | | 0 | -86 | 43 | 2 | | | | | |
| | | | | 0 | -42 | 21 | 2 | | | | |
| | | | | | 1 | -20 | 10 | 2 | | | |
| | | | | | | 1 | -10 | 5 | 2 | | |
| | | | | | | | 0 | -4 | 2 | 2 | |
| | | | | | | | | 1 | -2 | 1 | |
| | | | | | | | | | 0 | | |
|
the result of the conversion was:
275610 = 1010110001002
answer: AC416 = 1010110001002