This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
1347AF16 = 1 3 4 7 A F = 1(=0001) 3(=0011) 4(=0100) 7(=0111) A(=1010) F(=1111) = 1001101000111101011112
answer: 1347AF16 = 1001101000111101011112
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙165+3∙164+4∙163+7∙162+10∙161+15∙160 = 1∙1048576+3∙65536+4∙4096+7∙256+10∙16+15∙1 = 1048576+196608+16384+1792+160+15 = 126353510
got It: 1347AF16 =126353510
Translate the number 126353510 в binary like this:
the Integer part of the number is divided by the base of the new number system:
1263535 | 2 | | | | | | | | | | | | | | | | | | | | |
-1263534 | 631767 | 2 | | | | | | | | | | | | | | | | | | | |
1 | -631766 | 315883 | 2 | | | | | | | | | | | | | | | | | | |
| 1 | -315882 | 157941 | 2 | | | | | | | | | | | | | | | | | |
| | 1 | -157940 | 78970 | 2 | | | | | | | | | | | | | | | | |
| | | 1 | -78970 | 39485 | 2 | | | | | | | | | | | | | | | |
| | | | 0 | -39484 | 19742 | 2 | | | | | | | | | | | | | | |
| | | | | 1 | -19742 | 9871 | 2 | | | | | | | | | | | | | |
| | | | | | 0 | -9870 | 4935 | 2 | | | | | | | | | | | | |
| | | | | | | 1 | -4934 | 2467 | 2 | | | | | | | | | | | |
| | | | | | | | 1 | -2466 | 1233 | 2 | | | | | | | | | | |
| | | | | | | | | 1 | -1232 | 616 | 2 | | | | | | | | | |
| | | | | | | | | | 1 | -616 | 308 | 2 | | | | | | | | |
| | | | | | | | | | | 0 | -308 | 154 | 2 | | | | | | | |
| | | | | | | | | | | | 0 | -154 | 77 | 2 | | | | | | |
| | | | | | | | | | | | | 0 | -76 | 38 | 2 | | | | | |
| | | | | | | | | | | | | | 1 | -38 | 19 | 2 | | | | |
| | | | | | | | | | | | | | | 0 | -18 | 9 | 2 | | | |
| | | | | | | | | | | | | | | | 1 | -8 | 4 | 2 | | |
| | | | | | | | | | | | | | | | | 1 | -4 | 2 | 2 | |
| | | | | | | | | | | | | | | | | | 0 | -2 | 1 | |
| | | | | | | | | | | | | | | | | | | 0 | | |
|
the result of the conversion was:
126353510 = 1001101000111101011112
answer: 1347AF16 = 1001101000111101011112