This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
7∙81+2∙80 = 7∙8+2∙1 = 56+2 = 5810
got It: 728 =5810
Translate the number 5810 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
58 | 16 | |
-48 | 3 | |
A | | |
|
the result of the conversion was:
5810 = 3A16
answer: 728 = 3A16
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
728 = 7 2 = 7(=111) 2(=010) = 1110102
answer: 728 = 1110102
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
001110102 = 0011 1010 = 0011(=3) 1010(=A) = 3A16
answer: 001110108 = 3A16