This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the right
let\'s do a direct translation from binary to hexadecimal like this:
10100111.111011002 = 1010 0111. 1110 1100 = 1010(=A) 0111(=7). 1110(=E) 1100(=C) = A7.EC16
answer: 10100111.111011002 = A7.EC16
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙27+0∙26+1∙25+0∙24+0∙23+1∙22+1∙21+1∙20+1∙2-1+1∙2-2+1∙2-3+0∙2-4+1∙2-5+1∙2-6+0∙2-7+0∙2-8 = 1∙128+0∙64+1∙32+0∙16+0∙8+1∙4+1∙2+1∙1+1∙0.5+1∙0.25+1∙0.125+0∙0.0625+1∙0.03125+1∙0.015625+0∙0.0078125+0∙0.00390625 = 128+0+32+0+0+4+2+1+0.5+0.25+0.125+0+0.03125+0.015625+0+0 = 167.92187510
got It: 10100111.111011002 =167.92187510
Translate the number 167.92187510 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
167 | 16 | |
-160 | A | |
7 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 921875*16 |
E | .75*16 |
C | .0*16 |
the result of the conversion was:
167.92187510 = A7.EC16
answer: 10100111.111011002 = A7.EC16