This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
8∙167+8∙166+1∙165+1∙164+1∙163+0∙162+1∙161+5∙160 = 8∙268435456+8∙16777216+1∙1048576+1∙65536+1∙4096+0∙256+1∙16+5∙1 = 2147483648+134217728+1048576+65536+4096+0+16+5 = 228281960510
got It: 8811101516 =228281960510
Translate the number 228281960510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
2282819605 | 8 | | | | | | | | | | |
-2282819600 | 285352450 | 8 | | | | | | | | | |
5 | -285352448 | 35669056 | 8 | | | | | | | | |
| 2 | -35669056 | 4458632 | 8 | | | | | | | |
| | 0 | -4458632 | 557329 | 8 | | | | | | |
| | | 0 | -557328 | 69666 | 8 | | | | | |
| | | | 1 | -69664 | 8708 | 8 | | | | |
| | | | | 2 | -8704 | 1088 | 8 | | | |
| | | | | | 4 | -1088 | 136 | 8 | | |
| | | | | | | 0 | -136 | 17 | 8 | |
| | | | | | | | 0 | -16 | 2 | |
| | | | | | | | | 1 | | |
|
the result of the conversion was:
228281960510 = 210042100258
answer: 8811101516 = 210042100258
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
8811101516 = 8 8 1 1 1 0 1 5 = 8(=1000) 8(=1000) 1(=0001) 1(=0001) 1(=0001) 0(=0000) 1(=0001) 5(=0101) = 100010000001000100010000000101012
answer: 8811101516 = 100010000001000100010000000101012
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0100010000001000100010000000101012 = 010 001 000 000 100 010 001 000 000 010 101 = 010(=2) 001(=1) 000(=0) 000(=0) 100(=4) 010(=2) 001(=1) 000(=0) 000(=0) 010(=2) 101(=5) = 210042100258
answer: 8811101516 = 210042100258