This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
be16 = b e = b(=1011) e(=1110) = 101111102
answer: be16 = 101111102
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
11∙161+14∙160 = 11∙16+14∙1 = 176+14 = 19010
got It: be16 =19010
Translate the number 19010 в binary like this:
the Integer part of the number is divided by the base of the new number system:
190 | 2 | | | | | | | |
-190 | 95 | 2 | | | | | | |
0 | -94 | 47 | 2 | | | | | |
| 1 | -46 | 23 | 2 | | | | |
| | 1 | -22 | 11 | 2 | | | |
| | | 1 | -10 | 5 | 2 | | |
| | | | 1 | -4 | 2 | 2 | |
| | | | | 1 | -2 | 1 | |
| | | | | | 0 | | |
|
the result of the conversion was:
19010 = 101111102
answer: be16 = 101111102