This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s make a direct translation from binary to post-binary like this:
1101111011112 = 110 111 101 111 = 110(=6) 111(=7) 101(=5) 111(=7) = 67578
answer: 1101111011112 = 67578
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙211+1∙210+0∙29+1∙28+1∙27+1∙26+1∙25+0∙24+1∙23+1∙22+1∙21+1∙20 = 1∙2048+1∙1024+0∙512+1∙256+1∙128+1∙64+1∙32+0∙16+1∙8+1∙4+1∙2+1∙1 = 2048+1024+0+256+128+64+32+0+8+4+2+1 = 356710
got It: 1101111011112 =356710
Translate the number 356710 в octal like this:
the Integer part of the number is divided by the base of the new number system:
3567 | 8 | | | |
-3560 | 445 | 8 | | |
7 | -440 | 55 | 8 | |
| 5 | -48 | 6 | |
| | 7 | | |
|
the result of the conversion was:
356710 = 67578
answer: 1101111011112 = 67578