This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
7∙82+6∙81+2∙80+3∙8-1+3∙8-2 = 7∙64+6∙8+2∙1+3∙0.125+3∙0.015625 = 448+48+2+0.375+0.046875 = 498.42187510
got It: 762.338 =498.42187510
Translate the number 498.42187510 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
498 | 16 | | |
-496 | 31 | 16 | |
2 | -16 | 1 | |
| F | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 421875*16 |
6 | .75*16 |
C | .0*16 |
the result of the conversion was:
498.42187510 = 1F2.6C16
the Final answer: 762.338 = 1F2.6C16
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
762.338 = 7 6 2. 3 3 = 7(=111) 6(=110) 2(=010). 3(=011) 3(=011) = 111110010.0110112
the Final answer: 762.338 = 111110010.0110112
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s do a direct translation from binary to hexadecimal like this:
000111110010.011011002 = 0001 1111 0010. 0110 1100 = 0001(=1) 1111(=F) 0010(=2). 0110(=6) 1100(=C) = 1F2.6C16
the Final answer: 000111110010.011011008 = 1F2.6C16