This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
0010110001101011.111100102 = 0010 1100 0110 1011. 1111 0010 = 0010(=2) 1100(=C) 0110(=6) 1011(=B). 1111(=F) 0010(=2) = 2C6B.F216
answer: 0010110001101011.111100102 = 2C6B.F216
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙215+0∙214+1∙213+0∙212+1∙211+1∙210+0∙29+0∙28+0∙27+1∙26+1∙25+0∙24+1∙23+0∙22+1∙21+1∙20+1∙2-1+1∙2-2+1∙2-3+1∙2-4+0∙2-5+0∙2-6+1∙2-7+0∙2-8 = 0∙32768+0∙16384+1∙8192+0∙4096+1∙2048+1∙1024+0∙512+0∙256+0∙128+1∙64+1∙32+0∙16+1∙8+0∙4+1∙2+1∙1+1∙0.5+1∙0.25+1∙0.125+1∙0.0625+0∙0.03125+0∙0.015625+1∙0.0078125+0∙0.00390625 = 0+0+8192+0+2048+1024+0+0+0+64+32+0+8+0+2+1+0.5+0.25+0.125+0.0625+0+0+0.0078125+0 = 11371.945312510
got It: 0010110001101011.111100102 =11371.945312510
Translate the number 11371.945312510 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
11371 | 16 | | | |
-11360 | 710 | 16 | | |
B | -704 | 44 | 16 | |
| 6 | -32 | 2 | |
| | C | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 9453125*16 |
F | .125*16 |
2 | .0*16 |
the result of the conversion was:
11371.945312510 = 2C6B.F216
answer: 0010110001101011.111100102 = 2C6B.F216