This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
2∙83+6∙82+3∙81+5∙80+6∙8-1+0∙8-2 = 2∙512+6∙64+3∙8+5∙1+6∙0.125+0∙0.015625 = 1024+384+24+5+0.75+0 = 1437.7510
got It: 2635.608 =1437.7510
Translate the number 1437.7510 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
1437 | 16 | | |
-1424 | 89 | 16 | |
D | -80 | 5 | |
| 9 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 75*16 |
C | .0*16 |
the result of the conversion was:
1437.7510 = 59D.C16
answer: 2635.608 = 59D.C16
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
2635.608 = 2 6 3 5. 6 0 = 2(=010) 6(=110) 3(=011) 5(=101). 6(=110) 0(=000) = 010110011101.1100002
answer: 2635.608 = 10110011101.112
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s do a direct translation from binary to hexadecimal like this:
010110011101.11002 = 0101 1001 1101. 1100 = 0101(=5) 1001(=9) 1101(=D). 1100(=C) = 59D.C16
answer: 010110011101.11008 = 59D.C16