This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
A7D16 = A 7 D = A(=1010) 7(=0111) D(=1101) = 1010011111012
answer: A7D16 = 1010011111012
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
10∙162+7∙161+13∙160 = 10∙256+7∙16+13∙1 = 2560+112+13 = 268510
got It: A7D16 =268510
Translate the number 268510 в binary like this:
the Integer part of the number is divided by the base of the new number system:
2685 | 2 | | | | | | | | | | | |
-2684 | 1342 | 2 | | | | | | | | | | |
1 | -1342 | 671 | 2 | | | | | | | | | |
| 0 | -670 | 335 | 2 | | | | | | | | |
| | 1 | -334 | 167 | 2 | | | | | | | |
| | | 1 | -166 | 83 | 2 | | | | | | |
| | | | 1 | -82 | 41 | 2 | | | | | |
| | | | | 1 | -40 | 20 | 2 | | | | |
| | | | | | 1 | -20 | 10 | 2 | | | |
| | | | | | | 0 | -10 | 5 | 2 | | |
| | | | | | | | 0 | -4 | 2 | 2 | |
| | | | | | | | | 1 | -2 | 1 | |
| | | | | | | | | | 0 | | |
|
the result of the conversion was:
268510 = 1010011111012
answer: A7D16 = 1010011111012