This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
864516 = 8 6 4 5 = 8(=1000) 6(=0110) 4(=0100) 5(=0101) = 10000110010001012
answer: 864516 = 10000110010001012
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
8∙163+6∙162+4∙161+5∙160 = 8∙4096+6∙256+4∙16+5∙1 = 32768+1536+64+5 = 3437310
got It: 864516 =3437310
Translate the number 3437310 в binary like this:
the Integer part of the number is divided by the base of the new number system:
34373 | 2 | | | | | | | | | | | | | | | |
-34372 | 17186 | 2 | | | | | | | | | | | | | | |
1 | -17186 | 8593 | 2 | | | | | | | | | | | | | |
| 0 | -8592 | 4296 | 2 | | | | | | | | | | | | |
| | 1 | -4296 | 2148 | 2 | | | | | | | | | | | |
| | | 0 | -2148 | 1074 | 2 | | | | | | | | | | |
| | | | 0 | -1074 | 537 | 2 | | | | | | | | | |
| | | | | 0 | -536 | 268 | 2 | | | | | | | | |
| | | | | | 1 | -268 | 134 | 2 | | | | | | | |
| | | | | | | 0 | -134 | 67 | 2 | | | | | | |
| | | | | | | | 0 | -66 | 33 | 2 | | | | | |
| | | | | | | | | 1 | -32 | 16 | 2 | | | | |
| | | | | | | | | | 1 | -16 | 8 | 2 | | | |
| | | | | | | | | | | 0 | -8 | 4 | 2 | | |
| | | | | | | | | | | | 0 | -4 | 2 | 2 | |
| | | | | | | | | | | | | 0 | -2 | 1 | |
| | | | | | | | | | | | | | 0 | | |
|
the result of the conversion was:
3437310 = 10000110010001012
answer: 864516 = 10000110010001012