This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
F00016 = F 0 0 0 = F(=1111) 0(=0000) 0(=0000) 0(=0000) = 11110000000000002
answer: F00016 = 11110000000000002
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
15∙163+0∙162+0∙161+0∙160 = 15∙4096+0∙256+0∙16+0∙1 = 61440+0+0+0 = 6144010
got It: F00016 =6144010
Translate the number 6144010 в binary like this:
the Integer part of the number is divided by the base of the new number system:
61440 | 2 | | | | | | | | | | | | | | | |
-61440 | 30720 | 2 | | | | | | | | | | | | | | |
0 | -30720 | 15360 | 2 | | | | | | | | | | | | | |
| 0 | -15360 | 7680 | 2 | | | | | | | | | | | | |
| | 0 | -7680 | 3840 | 2 | | | | | | | | | | | |
| | | 0 | -3840 | 1920 | 2 | | | | | | | | | | |
| | | | 0 | -1920 | 960 | 2 | | | | | | | | | |
| | | | | 0 | -960 | 480 | 2 | | | | | | | | |
| | | | | | 0 | -480 | 240 | 2 | | | | | | | |
| | | | | | | 0 | -240 | 120 | 2 | | | | | | |
| | | | | | | | 0 | -120 | 60 | 2 | | | | | |
| | | | | | | | | 0 | -60 | 30 | 2 | | | | |
| | | | | | | | | | 0 | -30 | 15 | 2 | | | |
| | | | | | | | | | | 0 | -14 | 7 | 2 | | |
| | | | | | | | | | | | 1 | -6 | 3 | 2 | |
| | | | | | | | | | | | | 1 | -2 | 1 | |
| | | | | | | | | | | | | | 1 | | |
|
the result of the conversion was:
6144010 = 11110000000000002
answer: F00016 = 11110000000000002