This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
1∙161+3∙160 = 1∙16+3∙1 = 16+3 = 1910
got It: 1316 =1910
Translate the number 1910 в octal like this:
the Integer part of the number is divided by the base of the new number system:
19 | 8 | |
-16 | 2 | |
3 | | |
|
the result of the conversion was:
1910 = 238
answer: 1316 = 238
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
1316 = 1 3 = 1(=0001) 3(=0011) = 100112
answer: 1316 = 100112
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0100112 = 010 011 = 010(=2) 011(=3) = 238
answer: 1316 = 238