This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
ACFD16 = A C F D = A(=1010) C(=1100) F(=1111) D(=1101) = 10101100111111012
answer: ACFD16 = 10101100111111012
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
10∙163+12∙162+15∙161+13∙160 = 10∙4096+12∙256+15∙16+13∙1 = 40960+3072+240+13 = 4428510
got It: ACFD16 =4428510
Translate the number 4428510 в binary like this:
the Integer part of the number is divided by the base of the new number system:
44285 | 2 | | | | | | | | | | | | | | | |
-44284 | 22142 | 2 | | | | | | | | | | | | | | |
1 | -22142 | 11071 | 2 | | | | | | | | | | | | | |
| 0 | -11070 | 5535 | 2 | | | | | | | | | | | | |
| | 1 | -5534 | 2767 | 2 | | | | | | | | | | | |
| | | 1 | -2766 | 1383 | 2 | | | | | | | | | | |
| | | | 1 | -1382 | 691 | 2 | | | | | | | | | |
| | | | | 1 | -690 | 345 | 2 | | | | | | | | |
| | | | | | 1 | -344 | 172 | 2 | | | | | | | |
| | | | | | | 1 | -172 | 86 | 2 | | | | | | |
| | | | | | | | 0 | -86 | 43 | 2 | | | | | |
| | | | | | | | | 0 | -42 | 21 | 2 | | | | |
| | | | | | | | | | 1 | -20 | 10 | 2 | | | |
| | | | | | | | | | | 1 | -10 | 5 | 2 | | |
| | | | | | | | | | | | 0 | -4 | 2 | 2 | |
| | | | | | | | | | | | | 1 | -2 | 1 | |
| | | | | | | | | | | | | | 0 | | |
|
the result of the conversion was:
4428510 = 10101100111111012
answer: ACFD16 = 10101100111111012