This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
E8d616 = E 8 d 6 = E(=1110) 8(=1000) d(=1101) 6(=0110) = 11101000110101102
answer: E8d616 = 11101000110101102
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
14∙163+8∙162+13∙161+6∙160 = 14∙4096+8∙256+13∙16+6∙1 = 57344+2048+208+6 = 5960610
got It: E8d616 =5960610
Translate the number 5960610 в binary like this:
the Integer part of the number is divided by the base of the new number system:
59606 | 2 | | | | | | | | | | | | | | | |
-59606 | 29803 | 2 | | | | | | | | | | | | | | |
0 | -29802 | 14901 | 2 | | | | | | | | | | | | | |
| 1 | -14900 | 7450 | 2 | | | | | | | | | | | | |
| | 1 | -7450 | 3725 | 2 | | | | | | | | | | | |
| | | 0 | -3724 | 1862 | 2 | | | | | | | | | | |
| | | | 1 | -1862 | 931 | 2 | | | | | | | | | |
| | | | | 0 | -930 | 465 | 2 | | | | | | | | |
| | | | | | 1 | -464 | 232 | 2 | | | | | | | |
| | | | | | | 1 | -232 | 116 | 2 | | | | | | |
| | | | | | | | 0 | -116 | 58 | 2 | | | | | |
| | | | | | | | | 0 | -58 | 29 | 2 | | | | |
| | | | | | | | | | 0 | -28 | 14 | 2 | | | |
| | | | | | | | | | | 1 | -14 | 7 | 2 | | |
| | | | | | | | | | | | 0 | -6 | 3 | 2 | |
| | | | | | | | | | | | | 1 | -2 | 1 | |
| | | | | | | | | | | | | | 1 | | |
|
the result of the conversion was:
5960610 = 11101000110101102
answer: E8d616 = 11101000110101102