This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
12∙161+0∙160 = 12∙16+0∙1 = 192+0 = 19210
got It: C016 =19210
Translate the number 19210 в octal like this:
the Integer part of the number is divided by the base of the new number system:
192 | 8 | | |
-192 | 24 | 8 | |
0 | -24 | 3 | |
| 0 | | |
|
the result of the conversion was:
19210 = 3008
answer: C016 = 3008
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
C016 = C 0 = C(=1100) 0(=0000) = 110000002
answer: C016 = 110000002
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0110000002 = 011 000 000 = 011(=3) 000(=0) 000(=0) = 3008
answer: C016 = 3008