This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
2∙82+3∙81+2∙80+7∙8-1+6∙8-2 = 2∙64+3∙8+2∙1+7∙0.125+6∙0.015625 = 128+24+2+0.875+0.09375 = 154.9687510
got It: 232.768 =154.9687510
Translate the number 154.9687510 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
154 | 16 | |
-144 | 9 | |
A | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 96875*16 |
F | .5*16 |
8 | .0*16 |
the result of the conversion was:
154.9687510 = 9A.F816
answer: 232.768 = 9A.F816
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
232.768 = 2 3 2. 7 6 = 2(=010) 3(=011) 2(=010). 7(=111) 6(=110) = 010011010.1111102
answer: 232.768 = 10011010.111112
Fill in the number with missing zeros on the right
let\'s do a direct translation from binary to hexadecimal like this:
10011010.111110002 = 1001 1010. 1111 1000 = 1001(=9) 1010(=A). 1111(=F) 1000(=8) = 9A.F816
answer: 10011010.111110008 = 9A.F816