This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s make a direct translation from binary to post-binary like this:
1010010111002 = 101 001 011 100 = 101(=5) 001(=1) 011(=3) 100(=4) = 51348
the Final answer: 1010010111002 = 51348
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙211+0∙210+1∙29+0∙28+0∙27+1∙26+0∙25+1∙24+1∙23+1∙22+0∙21+0∙20 = 1∙2048+0∙1024+1∙512+0∙256+0∙128+1∙64+0∙32+1∙16+1∙8+1∙4+0∙2+0∙1 = 2048+0+512+0+0+64+0+16+8+4+0+0 = 265210
got It: 1010010111002 =265210
Translate the number 265210 в octal like this:
the Integer part of the number is divided by the base of the new number system:
2652 | 8 | | | |
-2648 | 331 | 8 | | |
4 | -328 | 41 | 8 | |
| 3 | -40 | 5 | |
| | 1 | | |
|
the result of the conversion was:
265210 = 51348
the Final answer: 1010010111002 = 51348