This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
76EE16 = 7 6 E E = 7(=0111) 6(=0110) E(=1110) E(=1110) = 1110110111011102
answer: 76EE16 = 1110110111011102
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
7∙163+6∙162+14∙161+14∙160 = 7∙4096+6∙256+14∙16+14∙1 = 28672+1536+224+14 = 3044610
got It: 76EE16 =3044610
Translate the number 3044610 в binary like this:
the Integer part of the number is divided by the base of the new number system:
30446 | 2 | | | | | | | | | | | | | | |
-30446 | 15223 | 2 | | | | | | | | | | | | | |
0 | -15222 | 7611 | 2 | | | | | | | | | | | | |
| 1 | -7610 | 3805 | 2 | | | | | | | | | | | |
| | 1 | -3804 | 1902 | 2 | | | | | | | | | | |
| | | 1 | -1902 | 951 | 2 | | | | | | | | | |
| | | | 0 | -950 | 475 | 2 | | | | | | | | |
| | | | | 1 | -474 | 237 | 2 | | | | | | | |
| | | | | | 1 | -236 | 118 | 2 | | | | | | |
| | | | | | | 1 | -118 | 59 | 2 | | | | | |
| | | | | | | | 0 | -58 | 29 | 2 | | | | |
| | | | | | | | | 1 | -28 | 14 | 2 | | | |
| | | | | | | | | | 1 | -14 | 7 | 2 | | |
| | | | | | | | | | | 0 | -6 | 3 | 2 | |
| | | | | | | | | | | | 1 | -2 | 1 | |
| | | | | | | | | | | | | 1 | | |
|
the result of the conversion was:
3044610 = 1110110111011102
answer: 76EE16 = 1110110111011102