This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0011101110112 = 001 110 111 011 = 001(=1) 110(=6) 111(=7) 011(=3) = 16738
answer: 011101110112 = 16738
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙211+0∙210+1∙29+1∙28+1∙27+0∙26+1∙25+1∙24+1∙23+0∙22+1∙21+1∙20 = 0∙2048+0∙1024+1∙512+1∙256+1∙128+0∙64+1∙32+1∙16+1∙8+0∙4+1∙2+1∙1 = 0+0+512+256+128+0+32+16+8+0+2+1 = 95510
got It: 0011101110112 =95510
Translate the number 95510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
955 | 8 | | | |
-952 | 119 | 8 | | |
3 | -112 | 14 | 8 | |
| 7 | -8 | 1 | |
| | 6 | | |
|
the result of the conversion was:
95510 = 16738
answer: 011101110112 = 16738